Solve 6(1+2)^2div9-16(1+(3-2)^3)

$$6 ( 1 + 2 ) ^ { 2 } \div 9 - 16 ( 1 + ( 3 - 2 ) ^ { 3 } )$$

Evaluate

$$-26$$

Solution Steps

Add 1 and 2 to get 3.

$$\frac{6\times 3^{2}}{9}-16\left(1+\left(3-2\right)^{3}\right)$$

Calculate 3 to the power of 2 and get 9.

$$\frac{6\times 9}{9}-16\left(1+\left(3-2\right)^{3}\right)$$

Multiply 6 and 9 to get 54.

$$\frac{54}{9}-16\left(1+\left(3-2\right)^{3}\right)$$

Divide 54 by 9 to get 6.

$$6-16\left(1+\left(3-2\right)^{3}\right)$$

Subtract 2 from 3 to get 1.

$$6-16\left(1+1^{3}\right)$$

Calculate 1 to the power of 3 and get 1.

$$6-16\left(1+1\right)$$

Add 1 and 1 to get 2.

$$6-16\times 2$$

Multiply 16 and 2 to get 32.

$$6-32$$

Subtract 32 from 6 to get -26.

$$-26$$

Factor

$$-26$$