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6x^{2}+3x^{2}+9=90
Use the distributive property to multiply 3 by x^{2}+3.
9x^{2}+9=90
Combine 6x^{2} and 3x^{2} to get 9x^{2}.
9x^{2}+9-90=0
Subtract 90 from both sides.
9x^{2}-81=0
Subtract 90 from 9 to get -81.
x^{2}-9=0
Divide both sides by 9.
\left(x-3\right)\left(x+3\right)=0
Consider x^{2}-9. Rewrite x^{2}-9 as x^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=3 x=-3
To find equation solutions, solve x-3=0 and x+3=0.
6x^{2}+3x^{2}+9=90
Use the distributive property to multiply 3 by x^{2}+3.
9x^{2}+9=90
Combine 6x^{2} and 3x^{2} to get 9x^{2}.
9x^{2}=90-9
Subtract 9 from both sides.
9x^{2}=81
Subtract 9 from 90 to get 81.
x^{2}=\frac{81}{9}
Divide both sides by 9.
x^{2}=9
Divide 81 by 9 to get 9.
x=3 x=-3
Take the square root of both sides of the equation.
6x^{2}+3x^{2}+9=90
Use the distributive property to multiply 3 by x^{2}+3.
9x^{2}+9=90
Combine 6x^{2} and 3x^{2} to get 9x^{2}.
9x^{2}+9-90=0
Subtract 90 from both sides.
9x^{2}-81=0
Subtract 90 from 9 to get -81.
x=\frac{0±\sqrt{0^{2}-4\times 9\left(-81\right)}}{2\times 9}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 9 for a, 0 for b, and -81 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 9\left(-81\right)}}{2\times 9}
Square 0.
x=\frac{0±\sqrt{-36\left(-81\right)}}{2\times 9}
Multiply -4 times 9.
x=\frac{0±\sqrt{2916}}{2\times 9}
Multiply -36 times -81.
x=\frac{0±54}{2\times 9}
Take the square root of 2916.
x=\frac{0±54}{18}
Multiply 2 times 9.
x=3
Now solve the equation x=\frac{0±54}{18} when ± is plus. Divide 54 by 18.
x=-3
Now solve the equation x=\frac{0±54}{18} when ± is minus. Divide -54 by 18.
x=3 x=-3
The equation is now solved.