Solve 6*6+5+3div9=

$$6 \times 6+5+3 \div 9=$$

Evaluate

$$\frac{124}{3}\approx 41.333333333$$

Solution Steps

Multiply 6 and 6 to get 36.

$$36+5+\frac{3}{9}$$

Add 36 and 5 to get 41.

$$41+\frac{3}{9}$$

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$41+\frac{1}{3}$$

Convert 41 to fraction \frac{123}{3}.

$$\frac{123}{3}+\frac{1}{3}$$

Since \frac{123}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{123+1}{3}$$

Add 123 and 1 to get 124.

$$\frac{124}{3}$$

Factor

$$\frac{2 ^ {2} \cdot 31}{3} = 41\frac{1}{3} = 41.333333333333336$$