Solve 6*3-20^2/-4*-16

$$6 \times 3- \frac{ { 20 }^{ 2 } }{ -4 \times -16 }$$

Evaluate

$$\frac{47}{4}=11.75$$

Solution Steps

Multiply 6 and 3 to get 18.

$$18-\frac{20^{2}}{-4\left(-16\right)}$$

Calculate 20 to the power of 2 and get 400.

$$18-\frac{400}{-4\left(-16\right)}$$

Multiply -4 and -16 to get 64.

$$18-\frac{400}{64}$$

Reduce the fraction \frac{400}{64} to lowest terms by extracting and canceling out 16.

$$18-\frac{25}{4}$$

Convert 18 to fraction \frac{72}{4}.

$$\frac{72}{4}-\frac{25}{4}$$

Since \frac{72}{4} and \frac{25}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{72-25}{4}$$

Subtract 25 from 72 to get 47.

$$\frac{47}{4}$$

Factor

$$\frac{47}{2 ^ {2}} = 11\frac{3}{4} = 11.75$$