Solve 6sqrt{7}+sqrt{48}-sqrt{50}=

$$6 \sqrt { 7 } + \sqrt { 48 } - \sqrt { 50 } =$$

Evaluate

$$4\sqrt{3}+6\sqrt{7}-5\sqrt{2}\approx 15.731643285$$

Solution Steps

Factor 48=4^{2}\times 3. Rewrite the square root of the product \sqrt{4^{2}\times 3} as the product of square roots \sqrt{4^{2}}\sqrt{3}. Take the square root of 4^{2}.

$$6\sqrt{7}+4\sqrt{3}-\sqrt{50}$$

Factor 50=5^{2}\times 2. Rewrite the square root of the product \sqrt{5^{2}\times 2} as the product of square roots \sqrt{5^{2}}\sqrt{2}. Take the square root of 5^{2}.

$$6\sqrt{7}+4\sqrt{3}-5\sqrt{2}$$