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\frac{24+1}{4}\times \frac{2\times 15+2}{15}-\frac{\frac{5\times 3+1}{3}}{\frac{8}{9}}
Multiply 6 and 4 to get 24.
\frac{25}{4}\times \frac{2\times 15+2}{15}-\frac{\frac{5\times 3+1}{3}}{\frac{8}{9}}
Add 24 and 1 to get 25.
\frac{25}{4}\times \frac{30+2}{15}-\frac{\frac{5\times 3+1}{3}}{\frac{8}{9}}
Multiply 2 and 15 to get 30.
\frac{25}{4}\times \frac{32}{15}-\frac{\frac{5\times 3+1}{3}}{\frac{8}{9}}
Add 30 and 2 to get 32.
\frac{25\times 32}{4\times 15}-\frac{\frac{5\times 3+1}{3}}{\frac{8}{9}}
Multiply \frac{25}{4} times \frac{32}{15} by multiplying numerator times numerator and denominator times denominator.
\frac{800}{60}-\frac{\frac{5\times 3+1}{3}}{\frac{8}{9}}
Do the multiplications in the fraction \frac{25\times 32}{4\times 15}.
\frac{40}{3}-\frac{\frac{5\times 3+1}{3}}{\frac{8}{9}}
Reduce the fraction \frac{800}{60} to lowest terms by extracting and canceling out 20.
\frac{40}{3}-\frac{\left(5\times 3+1\right)\times 9}{3\times 8}
Divide \frac{5\times 3+1}{3} by \frac{8}{9} by multiplying \frac{5\times 3+1}{3} by the reciprocal of \frac{8}{9}.
\frac{40}{3}-\frac{3\left(1+3\times 5\right)}{8}
Cancel out 3 in both numerator and denominator.
\frac{40}{3}-\frac{3\left(1+15\right)}{8}
Multiply 3 and 5 to get 15.
\frac{40}{3}-\frac{3\times 16}{8}
Add 1 and 15 to get 16.
\frac{40}{3}-\frac{48}{8}
Multiply 3 and 16 to get 48.
\frac{40}{3}-6
Divide 48 by 8 to get 6.
\frac{40}{3}-\frac{18}{3}
Convert 6 to fraction \frac{18}{3}.
\frac{40-18}{3}
Since \frac{40}{3} and \frac{18}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{22}{3}
Subtract 18 from 40 to get 22.