Solve 64/6+39/24

$$6 \frac { 4 } { 6 } + 3 \frac { 9 } { 24 }$$

Evaluate

$$\frac{241}{24}\approx 10.041666667$$

Solution Steps

Multiply 6 and 6 to get 36.

$$\frac{36+4}{6}+\frac{3\times 24+9}{24}$$

Add 36 and 4 to get 40.

$$\frac{40}{6}+\frac{3\times 24+9}{24}$$

Reduce the fraction \frac{40}{6} to lowest terms by extracting and canceling out 2.

$$\frac{20}{3}+\frac{3\times 24+9}{24}$$

Multiply 3 and 24 to get 72.

$$\frac{20}{3}+\frac{72+9}{24}$$

Add 72 and 9 to get 81.

$$\frac{20}{3}+\frac{81}{24}$$

Reduce the fraction \frac{81}{24} to lowest terms by extracting and canceling out 3.

$$\frac{20}{3}+\frac{27}{8}$$

Least common multiple of 3 and 8 is 24. Convert \frac{20}{3} and \frac{27}{8} to fractions with denominator 24.

$$\frac{160}{24}+\frac{81}{24}$$

Since \frac{160}{24} and \frac{81}{24} have the same denominator, add them by adding their numerators.

$$\frac{160+81}{24}$$

Add 160 and 81 to get 241.

$$\frac{241}{24}$$

Factor

$$\frac{241}{2 ^ {3} \cdot 3} = 10\frac{1}{24} = 10.041666666666666$$