Solve 64/5+71/3=

$$6 \frac { 4 } { 5 } + 7 \frac { 1 } { 3 } =$$

Evaluate

$$\frac{212}{15}\approx 14.133333333$$

Solution Steps

Multiply 6 and 5 to get 30.

$$\frac{30+4}{5}+\frac{7\times 3+1}{3}$$

Add 30 and 4 to get 34.

$$\frac{34}{5}+\frac{7\times 3+1}{3}$$

Multiply 7 and 3 to get 21.

$$\frac{34}{5}+\frac{21+1}{3}$$

Add 21 and 1 to get 22.

$$\frac{34}{5}+\frac{22}{3}$$

Least common multiple of 5 and 3 is 15. Convert \frac{34}{5} and \frac{22}{3} to fractions with denominator 15.

$$\frac{102}{15}+\frac{110}{15}$$

Since \frac{102}{15} and \frac{110}{15} have the same denominator, add them by adding their numerators.

$$\frac{102+110}{15}$$

Add 102 and 110 to get 212.

$$\frac{212}{15}$$

Factor

$$\frac{2 ^ {2} \cdot 53}{3 \cdot 5} = 14\frac{2}{15} = 14.133333333333333$$