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\frac{\left(6\times 7+3\right)\times 4}{7\left(2\times 4+1\right)}
Divide \frac{6\times 7+3}{7} by \frac{2\times 4+1}{4} by multiplying \frac{6\times 7+3}{7} by the reciprocal of \frac{2\times 4+1}{4}.
\frac{\left(42+3\right)\times 4}{7\left(2\times 4+1\right)}
Multiply 6 and 7 to get 42.
\frac{45\times 4}{7\left(2\times 4+1\right)}
Add 42 and 3 to get 45.
\frac{180}{7\left(2\times 4+1\right)}
Multiply 45 and 4 to get 180.
\frac{180}{7\left(8+1\right)}
Multiply 2 and 4 to get 8.
\frac{180}{7\times 9}
Add 8 and 1 to get 9.
\frac{180}{63}
Multiply 7 and 9 to get 63.
\frac{20}{7}
Reduce the fraction \frac{180}{63} to lowest terms by extracting and canceling out 9.