Solve 61/6+37/8

$$6 \frac { 1 } { 6 } + 3 \frac { 7 } { 8 }$$

Evaluate

$$\frac{241}{24}\approx 10.041666667$$

Solution Steps

Multiply 6 and 6 to get 36.

$$\frac{36+1}{6}+\frac{3\times 8+7}{8}$$

Add 36 and 1 to get 37.

$$\frac{37}{6}+\frac{3\times 8+7}{8}$$

Multiply 3 and 8 to get 24.

$$\frac{37}{6}+\frac{24+7}{8}$$

Add 24 and 7 to get 31.

$$\frac{37}{6}+\frac{31}{8}$$

Least common multiple of 6 and 8 is 24. Convert \frac{37}{6} and \frac{31}{8} to fractions with denominator 24.

$$\frac{148}{24}+\frac{93}{24}$$

Since \frac{148}{24} and \frac{93}{24} have the same denominator, add them by adding their numerators.

$$\frac{148+93}{24}$$

Add 148 and 93 to get 241.

$$\frac{241}{24}$$

Factor

$$\frac{241}{2 ^ {3} \cdot 3} = 10\frac{1}{24} = 10.041666666666666$$