Solve 6*(10-9)+7-2*2^3div2

$$6 \cdot ( 10 - 9 ) + 7 - 2 \cdot 2 ^ { 3 } \div 2$$

Evaluate

$$5$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$6\left(10-9\right)+7-\frac{2^{4}}{2}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 4 to get 3.

$$6\left(10-9\right)+7-2^{3}$$

Subtract 9 from 10 to get 1.

$$6\times 1+7-2^{3}$$

Multiply 6 and 1 to get 6.

$$6+7-2^{3}$$

Add 6 and 7 to get 13.

$$13-2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$13-8$$

Subtract 8 from 13 to get 5.

$$5$$

Factor

$$5$$