Solve 6*(5/2+3/2)+(2/3+7/3)

$$6 \cdot ( \frac { 5 } { 2 } + \frac { 3 } { 2 } ) + ( \frac { 2 } { 3 } + \frac { 7 } { 3 } )$$

Evaluate

$$27$$

Solution Steps

Since \frac{5}{2} and \frac{3}{2} have the same denominator, add them by adding their numerators.

$$6\times \frac{5+3}{2}+\frac{2}{3}+\frac{7}{3}$$

Add 5 and 3 to get 8.

$$6\times \frac{8}{2}+\frac{2}{3}+\frac{7}{3}$$

Divide 8 by 2 to get 4.

$$6\times 4+\frac{2}{3}+\frac{7}{3}$$

Multiply 6 and 4 to get 24.

$$24+\frac{2}{3}+\frac{7}{3}$$

Convert 24 to fraction \frac{72}{3}.

$$\frac{72}{3}+\frac{2}{3}+\frac{7}{3}$$

Since \frac{72}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{72+2}{3}+\frac{7}{3}$$

Add 72 and 2 to get 74.

$$\frac{74}{3}+\frac{7}{3}$$

Since \frac{74}{3} and \frac{7}{3} have the same denominator, add them by adding their numerators.

$$\frac{74+7}{3}$$

Add 74 and 7 to get 81.

$$\frac{81}{3}$$

Divide 81 by 3 to get 27.

$$27$$

Factor

$$3^{3}$$