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6^{4x-9}=216
Use the rules of exponents and logarithms to solve the equation.
\log(6^{4x-9})=\log(216)
Take the logarithm of both sides of the equation.
\left(4x-9\right)\log(6)=\log(216)
The logarithm of a number raised to a power is the power times the logarithm of the number.
4x-9=\frac{\log(216)}{\log(6)}
Divide both sides by \log(6).
4x-9=\log_{6}\left(216\right)
By the change-of-base formula log(a)/log(b)=log(b,a).
4x=3-\left(-9\right)
Add 9 to both sides of the equation.
x=\frac{12}{4}
Divide both sides by 4.