Solve 6^2-5^2=BC^2

$$6 ^ { 2 } - 5 ^ { 2 } = B C ^ { 2 }$$

Solve for B

$$B=\frac{11}{C^{2}}$$

$$C\neq 0$$

Steps for Solving Linear Equation

Calculate 6 to the power of 2 and get 36.

$$36-5^{2}=BC^{2}$$

Calculate 5 to the power of 2 and get 25.

$$36-25=BC^{2}$$

Subtract 25 from 36 to get 11.

$$11=BC^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$BC^{2}=11$$

The equation is in standard form.

$$C^{2}B=11$$

Divide both sides by C^{2}.

$$\frac{C^{2}B}{C^{2}}=\frac{11}{C^{2}}$$

Dividing by C^{2} undoes the multiplication by C^{2}.

$$B=\frac{11}{C^{2}}$$

Solve for C (complex solution)

$$C=-\sqrt{11}B^{-\frac{1}{2}}$$

$$C=\sqrt{11}B^{-\frac{1}{2}}\text{, }B\neq 0$$

Solve for C

$$C=\sqrt{\frac{11}{B}}$$

$$C=-\sqrt{\frac{11}{B}}\text{, }B>0$$