Solve 6+1+2+sqrt{3}+14/4

$$6 + 1 + 2 + \sqrt { 3 } + \frac { 14 } { 4 }$$

Evaluate

$$\sqrt{3}+\frac{25}{2}\approx 14.232050808$$

Solution Steps

Add 6 and 1 to get 7.

$$7+2+\sqrt{3}+\frac{14}{4}$$

Add 7 and 2 to get 9.

$$9+\sqrt{3}+\frac{14}{4}$$

Reduce the fraction \frac{14}{4} to lowest terms by extracting and canceling out 2.

$$9+\sqrt{3}+\frac{7}{2}$$

Convert 9 to fraction \frac{18}{2}.

$$\frac{18}{2}+\sqrt{3}+\frac{7}{2}$$

Since \frac{18}{2} and \frac{7}{2} have the same denominator, add them by adding their numerators.

$$\frac{18+7}{2}+\sqrt{3}$$

Add 18 and 7 to get 25.

$$\frac{25}{2}+\sqrt{3}$$

Factor

$$\frac{2 \sqrt{3} + 25}{2} = 14.232050807568877$$