Solve for x
x=\frac{4y+7}{5}
Solve for y
y=\frac{5x-7}{4}
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5x=7+4y
Add 4y to both sides.
5x=4y+7
The equation is in standard form.
\frac{5x}{5}=\frac{4y+7}{5}
Divide both sides by 5.
x=\frac{4y+7}{5}
Dividing by 5 undoes the multiplication by 5.
-4y=7-5x
Subtract 5x from both sides.
\frac{-4y}{-4}=\frac{7-5x}{-4}
Divide both sides by -4.
y=\frac{7-5x}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{5x-7}{4}
Divide 7-5x by -4.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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