Solve 5x*2x=10

$$5x \times 2x=10$$

Solve for x

$$x=1$$

$$x=-1$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$5x^{2}\times 2=10$$

Multiply 5 and 2 to get 10.

$$10x^{2}=10$$

Divide both sides by 10.

$$x^{2}=\frac{10}{10}$$

Divide 10 by 10 to get 1.

$$x^{2}=1$$

Take the square root of both sides of the equation.

$$x=1 x=-1$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$5x^{2}\times 2=10$$

Multiply 5 and 2 to get 10.

$$10x^{2}=10$$

Subtract 10 from both sides.

$$10x^{2}-10=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 10 for a, 0 for b, and -10 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 10\left(-10\right)}}{2\times 10}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 10\left(-10\right)}}{2\times 10}$$

Multiply -4 times 10.

$$x=\frac{0±\sqrt{-40\left(-10\right)}}{2\times 10}$$

Multiply -40 times -10.

$$x=\frac{0±\sqrt{400}}{2\times 10}$$

Take the square root of 400.

$$x=\frac{0±20}{2\times 10}$$

Multiply 2 times 10.

$$x=\frac{0±20}{20}$$

Now solve the equation x=\frac{0±20}{20} when ± is plus. Divide 20 by 20.

$$x=1$$

Now solve the equation x=\frac{0±20}{20} when ± is minus. Divide -20 by 20.

$$x=-1$$

The equation is now solved.

$$x=1 x=-1$$