Solve 56-45div5lceil90div3lfloor4-(25-31)rfloorrceil

$$56-45 \div 5 \lceil 90 \div 3 \lfloor 4-(25-31) \rfloor \rceil$$

Evaluate

$$-2644$$

Solution Steps

Divide 45 by 5 to get 9.

$$56-9\lceil \frac{90}{3}\lfloor 4-\left(25-31\right)\rfloor \rceil$$

Divide 90 by 3 to get 30.

$$56-9\lceil 30\lfloor 4-\left(25-31\right)\rfloor \rceil$$

Subtract 31 from 25 to get -6.

$$56-9\lceil 30\lfloor 4-\left(-6\right)\rfloor \rceil$$

The opposite of -6 is 6.

$$56-9\lceil 30\lfloor 4+6\rfloor \rceil$$

Add 4 and 6 to get 10.

$$56-9\lceil 30\lfloor 10\rfloor \rceil$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of 10 is 10.

$$56-9\lceil 30\times 10\rceil$$

Multiply 30 and 10 to get 300.

$$56-9\lceil 300\rceil$$

The ceiling of a real number a is the smallest integer number greater than or equal to a. The ceiling of 300 is 300.

$$56-9\times 300$$

Multiply 9 and 300 to get 2700.

$$56-2700$$

Subtract 2700 from 56 to get -2644.

$$-2644$$

Factor

$$-2644$$