Factor
2\left(3x+y^{3}\right)\left(9x^{2}-3xy^{3}+y^{6}\right)
Evaluate
2\left(27x^{3}+y^{9}\right)
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2\left(27x^{3}+y^{9}\right)
Factor out 2.
\left(3x+y^{3}\right)\left(9x^{2}-3xy^{3}+y^{6}\right)
Consider 27x^{3}+y^{9}. Rewrite 27x^{3}+y^{9} as \left(3x\right)^{3}+\left(y^{3}\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
2\left(3x+y^{3}\right)\left(9x^{2}-3xy^{3}+y^{6}\right)
Rewrite the complete factored expression.
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