Solve 52.6x*3.25x=6.3

$$52.6 x \times 3.25 x = 6.3$$

Solve for x

$$x=\frac{3\sqrt{47866}}{3419}\approx 0.191971042$$

$$x=-\frac{3\sqrt{47866}}{3419}\approx -0.191971042$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$52.6x^{2}\times 3.25=6.3$$

Multiply 52.6 and 3.25 to get 170.95.

$$170.95x^{2}=6.3$$

Divide both sides by 170.95.

$$x^{2}=\frac{6.3}{170.95}$$

Expand \frac{6.3}{170.95} by multiplying both numerator and the denominator by 100.

$$x^{2}=\frac{630}{17095}$$

Reduce the fraction \frac{630}{17095} to lowest terms by extracting and canceling out 5.

$$x^{2}=\frac{126}{3419}$$

Take the square root of both sides of the equation.

$$x=\frac{3\sqrt{47866}}{3419} x=-\frac{3\sqrt{47866}}{3419}$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$52.6x^{2}\times 3.25=6.3$$

Multiply 52.6 and 3.25 to get 170.95.

$$170.95x^{2}=6.3$$

Subtract 6.3 from both sides.

$$170.95x^{2}-6.3=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 170.95 for a, 0 for b, and -6.3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 170.95\left(-6.3\right)}}{2\times 170.95}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 170.95\left(-6.3\right)}}{2\times 170.95}$$

Multiply -4 times 170.95.

$$x=\frac{0±\sqrt{-683.8\left(-6.3\right)}}{2\times 170.95}$$

Multiply -683.8 times -6.3 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.

$$x=\frac{0±\sqrt{4307.94}}{2\times 170.95}$$

Take the square root of 4307.94.

$$x=\frac{0±\frac{3\sqrt{47866}}{10}}{2\times 170.95}$$

Multiply 2 times 170.95.

$$x=\frac{0±\frac{3\sqrt{47866}}{10}}{341.9}$$

Now solve the equation x=\frac{0±\frac{3\sqrt{47866}}{10}}{341.9} when ± is plus.

$$x=\frac{3\sqrt{47866}}{3419}$$

Now solve the equation x=\frac{0±\frac{3\sqrt{47866}}{10}}{341.9} when ± is minus.

$$x=-\frac{3\sqrt{47866}}{3419}$$

The equation is now solved.

$$x=\frac{3\sqrt{47866}}{3419} x=-\frac{3\sqrt{47866}}{3419}$$