Factor
8\left(4y+5z\right)\left(16y^{2}-20yz+25z^{2}\right)
Evaluate
512y^{3}+1000z^{3}
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8\left(64y^{3}+125z^{3}\right)
Factor out 8.
\left(4y+5z\right)\left(16y^{2}-20yz+25z^{2}\right)
Consider 64y^{3}+125z^{3}. Rewrite 64y^{3}+125z^{3} as \left(4y\right)^{3}+\left(5z\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
8\left(4y+5z\right)\left(16y^{2}-20yz+25z^{2}\right)
Rewrite the complete factored expression.
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