Solve for a
a=\frac{9c}{17b}
b\neq 0\text{ and }c\neq 0
Solve for b
b=\frac{9c}{17a}
a\neq 0\text{ and }c\neq 0
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51ab=27c
Multiply both sides of the equation by c.
51ba=27c
The equation is in standard form.
\frac{51ba}{51b}=\frac{27c}{51b}
Divide both sides by 51b.
a=\frac{27c}{51b}
Dividing by 51b undoes the multiplication by 51b.
a=\frac{9c}{17b}
Divide 27c by 51b.
51ab=27c
Multiply both sides of the equation by c.
\frac{51ab}{51a}=\frac{27c}{51a}
Divide both sides by 51a.
b=\frac{27c}{51a}
Dividing by 51a undoes the multiplication by 51a.
b=\frac{9c}{17a}
Divide 27c by 51a.
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