Solve 500-[(3*48)-(3*48*15/100)]

$$500 - [ ( 3 \times 48 ) - ( 3 \times 48 \times \frac { 15 } { 100 } ) ]$$

Evaluate

$$\frac{1888}{5}=377.6$$

Solution Steps

Multiply 3 and 48 to get 144.

$$500-\left(144-3\times 48\times \frac{15}{100}\right)$$

Multiply 3 and 48 to get 144.

$$500-\left(144-144\times \frac{15}{100}\right)$$

Reduce the fraction \frac{15}{100} to lowest terms by extracting and canceling out 5.

$$500-\left(144-144\times \frac{3}{20}\right)$$

Express 144\times \frac{3}{20} as a single fraction.

$$500-\left(144-\frac{144\times 3}{20}\right)$$

Multiply 144 and 3 to get 432.

$$500-\left(144-\frac{432}{20}\right)$$

Reduce the fraction \frac{432}{20} to lowest terms by extracting and canceling out 4.

$$500-\left(144-\frac{108}{5}\right)$$

Convert 144 to fraction \frac{720}{5}.

$$500-\left(\frac{720}{5}-\frac{108}{5}\right)$$

Since \frac{720}{5} and \frac{108}{5} have the same denominator, subtract them by subtracting their numerators.

$$500-\frac{720-108}{5}$$

Subtract 108 from 720 to get 612.

$$500-\frac{612}{5}$$

Convert 500 to fraction \frac{2500}{5}.

$$\frac{2500}{5}-\frac{612}{5}$$

Since \frac{2500}{5} and \frac{612}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2500-612}{5}$$

Subtract 612 from 2500 to get 1888.

$$\frac{1888}{5}$$

Factor

$$\frac{2 ^ {5} \cdot 59}{5} = 377\frac{3}{5} = 377.6$$