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\frac{10}{2}-\frac{1}{3}x-\frac{1}{2}=\frac{1}{4}x
Convert 5 to fraction \frac{10}{2}.
\frac{10-1}{2}-\frac{1}{3}x=\frac{1}{4}x
Since \frac{10}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{9}{2}-\frac{1}{3}x=\frac{1}{4}x
Subtract 1 from 10 to get 9.
\frac{9}{2}-\frac{1}{3}x-\frac{1}{4}x=0
Subtract \frac{1}{4}x from both sides.
\frac{9}{2}-\frac{7}{12}x=0
Combine -\frac{1}{3}x and -\frac{1}{4}x to get -\frac{7}{12}x.
-\frac{7}{12}x=-\frac{9}{2}
Subtract \frac{9}{2} from both sides. Anything subtracted from zero gives its negation.
x=-\frac{9}{2}\left(-\frac{12}{7}\right)
Multiply both sides by -\frac{12}{7}, the reciprocal of -\frac{7}{12}.
x=\frac{-9\left(-12\right)}{2\times 7}
Multiply -\frac{9}{2} times -\frac{12}{7} by multiplying numerator times numerator and denominator times denominator.
x=\frac{108}{14}
Do the multiplications in the fraction \frac{-9\left(-12\right)}{2\times 7}.
x=\frac{54}{7}
Reduce the fraction \frac{108}{14} to lowest terms by extracting and canceling out 2.