Solve 5x_{2}-8x-4=0

$$5 x _ { 2 } - 8 x - 4 = 0$$

Solve for x

$$x=\frac{5x_{2}}{8}-\frac{1}{2}$$

Steps for Solving Linear Equation

Subtract 5x_{2} from both sides. Anything subtracted from zero gives its negation.

$$-8x-4=-5x_{2}$$

Add 4 to both sides.

$$-8x=-5x_{2}+4$$

The equation is in standard form.

$$-8x=4-5x_{2}$$

Divide both sides by -8.

$$\frac{-8x}{-8}=\frac{4-5x_{2}}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$x=\frac{4-5x_{2}}{-8}$$

Divide -5x_{2}+4 by -8.

$$x=\frac{5x_{2}}{8}-\frac{1}{2}$$

Solve for x_2

$$x_{2}=\frac{8x+4}{5}$$

Steps for Solving Linear Equation

Add 8x to both sides. Anything plus zero gives itself.

$$5x_{2}-4=8x$$

Add 4 to both sides.

$$5x_{2}=8x+4$$

Divide both sides by 5.

$$\frac{5x_{2}}{5}=\frac{8x+4}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$x_{2}=\frac{8x+4}{5}$$