Solve 5x1-2y-3=0

$$5 x 1 - 2 y - 3 = 0$$

Solve for x_1

$$x_{1}=\frac{2y+3}{5}$$

Steps for Solving Linear Equation

Add 2y to both sides. Anything plus zero gives itself.

$$5x_{1}-3=2y$$

Add 3 to both sides.

$$5x_{1}=2y+3$$

Divide both sides by 5.

$$\frac{5x_{1}}{5}=\frac{2y+3}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$x_{1}=\frac{2y+3}{5}$$

Solve for y

$$y=\frac{5x_{1}-3}{2}$$

Steps for Solving Linear Equation

Subtract 5x_{1} from both sides. Anything subtracted from zero gives its negation.

$$-2y-3=-5x_{1}$$

Add 3 to both sides.

$$-2y=-5x_{1}+3$$

The equation is in standard form.

$$-2y=3-5x_{1}$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{3-5x_{1}}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{3-5x_{1}}{-2}$$

Divide -5x_{1}+3 by -2.

$$y=\frac{5x_{1}-3}{2}$$