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Solve for I
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3x-10I=5x-8
Swap sides so that all variable terms are on the left hand side.
-10I=5x-8-3x
Subtract 3x from both sides.
-10I=2x-8
Combine 5x and -3x to get 2x.
\frac{-10I}{-10}=\frac{2x-8}{-10}
Divide both sides by -10.
I=\frac{2x-8}{-10}
Dividing by -10 undoes the multiplication by -10.
I=\frac{4-x}{5}
Divide -8+2x by -10.
5x-8-3x=-10I
Subtract 3x from both sides.
2x-8=-10I
Combine 5x and -3x to get 2x.
2x=-10I+8
Add 8 to both sides.
2x=8-10I
The equation is in standard form.
\frac{2x}{2}=\frac{8-10I}{2}
Divide both sides by 2.
x=\frac{8-10I}{2}
Dividing by 2 undoes the multiplication by 2.
x=4-5I
Divide -10I+8 by 2.