Solve 5x(x)=180

$$5 x ( x ) = 180$$

Solve for x

$$x=6$$

$$x=-6$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$5x^{2}=180$$

Divide both sides by 5.

$$x^{2}=\frac{180}{5}$$

Divide 180 by 5 to get 36.

$$x^{2}=36$$

Take the square root of both sides of the equation.

$$x=6 x=-6$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$5x^{2}=180$$

Subtract 180 from both sides.

$$5x^{2}-180=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -180 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 5\left(-180\right)}}{2\times 5}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 5\left(-180\right)}}{2\times 5}$$

Multiply -4 times 5.

$$x=\frac{0±\sqrt{-20\left(-180\right)}}{2\times 5}$$

Multiply -20 times -180.

$$x=\frac{0±\sqrt{3600}}{2\times 5}$$

Take the square root of 3600.

$$x=\frac{0±60}{2\times 5}$$

Multiply 2 times 5.

$$x=\frac{0±60}{10}$$

Now solve the equation x=\frac{0±60}{10} when ± is plus. Divide 60 by 10.

$$x=6$$

Now solve the equation x=\frac{0±60}{10} when ± is minus. Divide -60 by 10.

$$x=-6$$

The equation is now solved.

$$x=6 x=-6$$