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5\left(x^{3}+9x^{2}+14x\right)
Factor out 5.
x\left(x^{2}+9x+14\right)
Consider x^{3}+9x^{2}+14x. Factor out x.
a+b=9 ab=1\times 14=14
Consider x^{2}+9x+14. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+14. To find a and b, set up a system to be solved.
1,14 2,7
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 14.
1+14=15 2+7=9
Calculate the sum for each pair.
a=2 b=7
The solution is the pair that gives sum 9.
\left(x^{2}+2x\right)+\left(7x+14\right)
Rewrite x^{2}+9x+14 as \left(x^{2}+2x\right)+\left(7x+14\right).
x\left(x+2\right)+7\left(x+2\right)
Factor out x in the first and 7 in the second group.
\left(x+2\right)\left(x+7\right)
Factor out common term x+2 by using distributive property.
5x\left(x+2\right)\left(x+7\right)
Rewrite the complete factored expression.