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y\left(5x^{2}-11x+6\right)
Factor out y.
a+b=-11 ab=5\times 6=30
Consider 5x^{2}-11x+6. Factor the expression by grouping. First, the expression needs to be rewritten as 5x^{2}+ax+bx+6. To find a and b, set up a system to be solved.
-1,-30 -2,-15 -3,-10 -5,-6
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 30.
-1-30=-31 -2-15=-17 -3-10=-13 -5-6=-11
Calculate the sum for each pair.
a=-6 b=-5
The solution is the pair that gives sum -11.
\left(5x^{2}-6x\right)+\left(-5x+6\right)
Rewrite 5x^{2}-11x+6 as \left(5x^{2}-6x\right)+\left(-5x+6\right).
x\left(5x-6\right)-\left(5x-6\right)
Factor out x in the first and -1 in the second group.
\left(5x-6\right)\left(x-1\right)
Factor out common term 5x-6 by using distributive property.
y\left(5x-6\right)\left(x-1\right)
Rewrite the complete factored expression.