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5x^{2}=1900+4
Add 4 to both sides.
5x^{2}=1904
Add 1900 and 4 to get 1904.
x^{2}=\frac{1904}{5}
Divide both sides by 5.
x=\frac{4\sqrt{595}}{5} x=-\frac{4\sqrt{595}}{5}
Take the square root of both sides of the equation.
5x^{2}-4-1900=0
Subtract 1900 from both sides.
5x^{2}-1904=0
Subtract 1900 from -4 to get -1904.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-1904\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -1904 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-1904\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-1904\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{38080}}{2\times 5}
Multiply -20 times -1904.
x=\frac{0±8\sqrt{595}}{2\times 5}
Take the square root of 38080.
x=\frac{0±8\sqrt{595}}{10}
Multiply 2 times 5.
x=\frac{4\sqrt{595}}{5}
Now solve the equation x=\frac{0±8\sqrt{595}}{10} when ± is plus.
x=-\frac{4\sqrt{595}}{5}
Now solve the equation x=\frac{0±8\sqrt{595}}{10} when ± is minus.
x=\frac{4\sqrt{595}}{5} x=-\frac{4\sqrt{595}}{5}
The equation is now solved.