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a+b=-36 ab=5\left(-81\right)=-405
Factor the expression by grouping. First, the expression needs to be rewritten as 5x^{2}+ax+bx-81. To find a and b, set up a system to be solved.
1,-405 3,-135 5,-81 9,-45 15,-27
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -405.
1-405=-404 3-135=-132 5-81=-76 9-45=-36 15-27=-12
Calculate the sum for each pair.
a=-45 b=9
The solution is the pair that gives sum -36.
\left(5x^{2}-45x\right)+\left(9x-81\right)
Rewrite 5x^{2}-36x-81 as \left(5x^{2}-45x\right)+\left(9x-81\right).
5x\left(x-9\right)+9\left(x-9\right)
Factor out 5x in the first and 9 in the second group.
\left(x-9\right)\left(5x+9\right)
Factor out common term x-9 by using distributive property.
5x^{2}-36x-81=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-\left(-36\right)±\sqrt{\left(-36\right)^{2}-4\times 5\left(-81\right)}}{2\times 5}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-36\right)±\sqrt{1296-4\times 5\left(-81\right)}}{2\times 5}
Square -36.
x=\frac{-\left(-36\right)±\sqrt{1296-20\left(-81\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{-\left(-36\right)±\sqrt{1296+1620}}{2\times 5}
Multiply -20 times -81.
x=\frac{-\left(-36\right)±\sqrt{2916}}{2\times 5}
Add 1296 to 1620.
x=\frac{-\left(-36\right)±54}{2\times 5}
Take the square root of 2916.
x=\frac{36±54}{2\times 5}
The opposite of -36 is 36.
x=\frac{36±54}{10}
Multiply 2 times 5.
x=\frac{90}{10}
Now solve the equation x=\frac{36±54}{10} when ± is plus. Add 36 to 54.
x=9
Divide 90 by 10.
x=-\frac{18}{10}
Now solve the equation x=\frac{36±54}{10} when ± is minus. Subtract 54 from 36.
x=-\frac{9}{5}
Reduce the fraction \frac{-18}{10} to lowest terms by extracting and canceling out 2.
5x^{2}-36x-81=5\left(x-9\right)\left(x-\left(-\frac{9}{5}\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 9 for x_{1} and -\frac{9}{5} for x_{2}.
5x^{2}-36x-81=5\left(x-9\right)\left(x+\frac{9}{5}\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.
5x^{2}-36x-81=5\left(x-9\right)\times \frac{5x+9}{5}
Add \frac{9}{5} to x by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
5x^{2}-36x-81=\left(x-9\right)\left(5x+9\right)
Cancel out 5, the greatest common factor in 5 and 5.
x ^ 2 -\frac{36}{5}x -\frac{81}{5} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 5
r + s = \frac{36}{5} rs = -\frac{81}{5}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{18}{5} - u s = \frac{18}{5} + u
Two numbers r and s sum up to \frac{36}{5} exactly when the average of the two numbers is \frac{1}{2}*\frac{36}{5} = \frac{18}{5}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{18}{5} - u) (\frac{18}{5} + u) = -\frac{81}{5}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{81}{5}
\frac{324}{25} - u^2 = -\frac{81}{5}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{81}{5}-\frac{324}{25} = -\frac{729}{25}
Simplify the expression by subtracting \frac{324}{25} on both sides
u^2 = \frac{729}{25} u = \pm\sqrt{\frac{729}{25}} = \pm \frac{27}{5}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{18}{5} - \frac{27}{5} = -1.800 s = \frac{18}{5} + \frac{27}{5} = 9
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.