Solve 5x^2-3y=4y+8

$$5 x ^ { 2 } - 3 y = 4 y + 8$$

Solve for y

$$y=\frac{5x^{2}-8}{7}$$

Steps for Solving Linear Equation

Subtract 4y from both sides.

$$5x^{2}-3y-4y=8$$

Combine -3y and -4y to get -7y.

$$5x^{2}-7y=8$$

Subtract 5x^{2} from both sides.

$$-7y=8-5x^{2}$$

Divide both sides by -7.

$$\frac{-7y}{-7}=\frac{8-5x^{2}}{-7}$$

Dividing by -7 undoes the multiplication by -7.

$$y=\frac{8-5x^{2}}{-7}$$

Divide 8-5x^{2} by -7.

$$y=\frac{5x^{2}-8}{7}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{35y+40}}{5}$$

$$x=\frac{\sqrt{35y+40}}{5}$$

Solve for x

$$x=\frac{\sqrt{35y+40}}{5}$$

$$x=-\frac{\sqrt{35y+40}}{5}\text{, }y\geq -\frac{8}{7}$$