Solve 5x^2-3x+2>0

$$5 x ^ { 2 } - 3 x + 2 > 0$$

Solve for x

$$x\in \mathrm{R}$$

Steps Using the Quadratic Formula

To solve the inequality, factor the left hand side. Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$5x^{2}-3x+2=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 5 for a, -3 for b, and 2 for c in the quadratic formula.

$$x=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}-4\times 5\times 2}}{2\times 5}$$

Do the calculations.

$$x=\frac{3±\sqrt{-31}}{10}$$

Since the square root of a negative number is not defined in the real field, there are no solutions. Expression 5x^{2}-3x+2 has the same sign for any x. To determine the sign, calculate the value of the expression for x=0.

$$5\times 0^{2}-3\times 0+2=2$$

The value of the expression 5x^{2}-3x+2 is always positive. Inequality holds for x\in \mathrm{R}.

$$x\in \mathrm{R}$$