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5x^{2}=8-4
Subtract 4 from both sides.
5x^{2}=4
Subtract 4 from 8 to get 4.
x^{2}=\frac{4}{5}
Divide both sides by 5.
x=\frac{2\sqrt{5}}{5} x=-\frac{2\sqrt{5}}{5}
Take the square root of both sides of the equation.
5x^{2}+4-8=0
Subtract 8 from both sides.
5x^{2}-4=0
Subtract 8 from 4 to get -4.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-4\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-4\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-4\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{80}}{2\times 5}
Multiply -20 times -4.
x=\frac{0±4\sqrt{5}}{2\times 5}
Take the square root of 80.
x=\frac{0±4\sqrt{5}}{10}
Multiply 2 times 5.
x=\frac{2\sqrt{5}}{5}
Now solve the equation x=\frac{0±4\sqrt{5}}{10} when ± is plus.
x=-\frac{2\sqrt{5}}{5}
Now solve the equation x=\frac{0±4\sqrt{5}}{10} when ± is minus.
x=\frac{2\sqrt{5}}{5} x=-\frac{2\sqrt{5}}{5}
The equation is now solved.