Solve for b
b=\frac{5\left(x+3\right)}{6}
Solve for x
x=\frac{6b}{5}-3
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6b-15=5x
Swap sides so that all variable terms are on the left hand side.
6b=5x+15
Add 15 to both sides.
\frac{6b}{6}=\frac{5x+15}{6}
Divide both sides by 6.
b=\frac{5x+15}{6}
Dividing by 6 undoes the multiplication by 6.
b=\frac{5x}{6}+\frac{5}{2}
Divide 15+5x by 6.
5x=6b-15
The equation is in standard form.
\frac{5x}{5}=\frac{6b-15}{5}
Divide both sides by 5.
x=\frac{6b-15}{5}
Dividing by 5 undoes the multiplication by 5.
x=\frac{6b}{5}-3
Divide 6b-15 by 5.
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