Solve 5x=-14a^2bdiv2a=

$$5 x = - 14 a ^ { 2 } b \div 2 a =$$

Solve for b

$$\left\{\begin{matrix}b=-\frac{5x}{7a^{3}}\text{, }&a\neq 0\\b\in \mathrm{R}\text{, }&x=0\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$10x=-14a^{2}ba$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$10x=-14a^{3}b$$

Swap sides so that all variable terms are on the left hand side.

$$-14a^{3}b=10x$$

The equation is in standard form.

$$\left(-14a^{3}\right)b=10x$$

Divide both sides by -14a^{3}.

$$\frac{\left(-14a^{3}\right)b}{-14a^{3}}=\frac{10x}{-14a^{3}}$$

Dividing by -14a^{3} undoes the multiplication by -14a^{3}.

$$b=\frac{10x}{-14a^{3}}$$

Divide 10x by -14a^{3}.

$$b=-\frac{5x}{7a^{3}}$$

Solve for a

$$\left\{\begin{matrix}a=-\frac{7^{\frac{2}{3}}\sqrt[3]{\frac{5x}{b}}}{7}\text{, }&b\neq 0\\a\in \mathrm{R}\text{, }&x=0\text{ and }b=0\end{matrix}\right.$$