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5w^{2}\left(w-1\right)+9\left(w-1\right)
Do the grouping 5w^{3}-9-5w^{2}+9w=\left(5w^{3}-5w^{2}\right)+\left(9w-9\right), and factor out 5w^{2} in the first and 9 in the second group.
\left(w-1\right)\left(5w^{2}+9\right)
Factor out common term w-1 by using distributive property. Polynomial 5w^{2}+9 is not factored since it does not have any rational roots.