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±\frac{2}{5},±2,±\frac{1}{5},±1
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 2 and q divides the leading coefficient 5. List all candidates \frac{p}{q}.
t=1
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
5t^{2}+5t-2=0
By Factor theorem, t-k is a factor of the polynomial for each root k. Divide 5t^{3}-7t+2 by t-1 to get 5t^{2}+5t-2. Solve the equation where the result equals to 0.
t=\frac{-5±\sqrt{5^{2}-4\times 5\left(-2\right)}}{2\times 5}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 5 for a, 5 for b, and -2 for c in the quadratic formula.
t=\frac{-5±\sqrt{65}}{10}
Do the calculations.
t=-\frac{\sqrt{65}}{10}-\frac{1}{2} t=\frac{\sqrt{65}}{10}-\frac{1}{2}
Solve the equation 5t^{2}+5t-2=0 when ± is plus and when ± is minus.
t=1 t=-\frac{\sqrt{65}}{10}-\frac{1}{2} t=\frac{\sqrt{65}}{10}-\frac{1}{2}
List all found solutions.