Solve 5q=3/u-5

$$5 q = \frac { 3 } { u } - 5$$

Solve for q

$$q=-1+\frac{3}{5u}$$

$$u\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by u.

$$5qu=3+u\left(-5\right)$$

The equation is in standard form.

$$5uq=3-5u$$

Divide both sides by 5u.

$$\frac{5uq}{5u}=\frac{3-5u}{5u}$$

Dividing by 5u undoes the multiplication by 5u.

$$q=\frac{3-5u}{5u}$$

Divide 3-5u by 5u.

$$q=-1+\frac{3}{5u}$$

Solve for u

$$u=\frac{3}{5\left(q+1\right)}$$

$$q\neq -1$$

Steps for Solving Linear Equation

Variable u cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by u.

$$5qu=3+u\left(-5\right)$$

Subtract u\left(-5\right) from both sides.

$$5qu-u\left(-5\right)=3$$

Multiply -1 and -5 to get 5.

$$5qu+5u=3$$

Combine all terms containing u.

$$\left(5q+5\right)u=3$$

Divide both sides by 5+5q.

$$\frac{\left(5q+5\right)u}{5q+5}=\frac{3}{5q+5}$$

Dividing by 5+5q undoes the multiplication by 5+5q.

$$u=\frac{3}{5q+5}$$

Divide 3 by 5+5q.

$$u=\frac{3}{5\left(q+1\right)}$$

Variable u cannot be equal to 0.

$$u=\frac{3}{5\left(q+1\right)}\text{, }u\neq 0$$