Solve 5a^4b^8*9a^2b^3

$$5 a ^ { 4 } b ^ { 8 } \times 9 a ^ { 2 } b ^ { 3 }$$

Evaluate

$$45a^{6}b^{11}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$5^{1}a^{4}b^{8}\times 9^{1}a^{2}b^{3}$$

Use the Commutative Property of Multiplication.

$$5^{1}\times 9^{1}a^{4}a^{2}b^{8}b^{3}$$

To multiply powers of the same base, add their exponents.

$$5^{1}\times 9^{1}a^{4+2}b^{8+3}$$

Add the exponents 4 and 2.

$$5^{1}\times 9^{1}a^{6}b^{8+3}$$

Add the exponents 8 and 3.

$$5^{1}\times 9^{1}a^{6}b^{11}$$

Multiply 5 times 9.

$$45a^{6}b^{11}$$

Differentiate w.r.t. a

$$270a^{5}b^{11}$$