Solve for a
a=\frac{17-c-3b}{5}
Solve for b
b=\frac{17-c-5a}{3}
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5a+c=17-3b
Subtract 3b from both sides.
5a=17-3b-c
Subtract c from both sides.
5a=17-c-3b
The equation is in standard form.
\frac{5a}{5}=\frac{17-c-3b}{5}
Divide both sides by 5.
a=\frac{17-c-3b}{5}
Dividing by 5 undoes the multiplication by 5.
3b+c=17-5a
Subtract 5a from both sides.
3b=17-5a-c
Subtract c from both sides.
3b=17-c-5a
The equation is in standard form.
\frac{3b}{3}=\frac{17-c-5a}{3}
Divide both sides by 3.
b=\frac{17-c-5a}{3}
Dividing by 3 undoes the multiplication by 3.
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