Solve 5-8xgeq4x+1

$$5 - 8 x \geq 4 x + 1$$

Solve for x

$$x\leq \frac{1}{3}$$

Solution Steps

Subtract 4x from both sides.

$$5-8x-4x\geq 1$$

Combine -8x and -4x to get -12x.

$$5-12x\geq 1$$

Subtract 5 from both sides.

$$-12x\geq 1-5$$

Subtract 5 from 1 to get -4.

$$-12x\geq -4$$

Divide both sides by -12. Since -12 is negative, the inequality direction is changed.

$$x\leq \frac{-4}{-12}$$

Reduce the fraction \frac{-4}{-12} to lowest terms by extracting and canceling out -4.

$$x\leq \frac{1}{3}$$