Solve 5-3y-(4-2y)=y-8-(y-1)

$$5 - 3 y - ( 4 - 2 y ) = y - 8 - ( y - 1 )$$

Solve for y

$$y=8$$

Steps for Solving Linear Equation

To find the opposite of 4-2y, find the opposite of each term.

$$5-3y-4-\left(-2y\right)=y-8-\left(y-1\right)$$

The opposite of -2y is 2y.

$$5-3y-4+2y=y-8-\left(y-1\right)$$

Subtract 4 from 5 to get 1.

$$1-3y+2y=y-8-\left(y-1\right)$$

Combine -3y and 2y to get -y.

$$1-y=y-8-\left(y-1\right)$$

To find the opposite of y-1, find the opposite of each term.

$$1-y=y-8-y-\left(-1\right)$$

The opposite of -1 is 1.

$$1-y=y-8-y+1$$

Combine y and -y to get 0.

$$1-y=-8+1$$

Add -8 and 1 to get -7.

$$1-y=-7$$

Subtract 1 from both sides.

$$-y=-7-1$$

Subtract 1 from -7 to get -8.

$$-y=-8$$

Multiply both sides by -1.

$$y=8$$