Solve 5-3xleq3+9x

$$5 - 3 x \leq 3 + 9 x$$

Solve for x

$$x\geq \frac{1}{6}$$

Solution Steps

Subtract 9x from both sides.

$$5-3x-9x\leq 3$$

Combine -3x and -9x to get -12x.

$$5-12x\leq 3$$

Subtract 5 from both sides.

$$-12x\leq 3-5$$

Subtract 5 from 3 to get -2.

$$-12x\leq -2$$

Divide both sides by -12. Since -12 is negative, the inequality direction is changed.

$$x\geq \frac{-2}{-12}$$

Reduce the fraction \frac{-2}{-12} to lowest terms by extracting and canceling out -2.

$$x\geq \frac{1}{6}$$