Solve 5-3(4x-7)geq(4x+3)2

$$5 - 3 ( 4 x - 7 ) \geq ( 4 x + 3 ) 2$$

Solve for x

$$x\leq 1$$

Solution Steps

Use the distributive property to multiply -3 by 4x-7.

$$5-12x+21\geq \left(4x+3\right)\times 2$$

Add 5 and 21 to get 26.

$$26-12x\geq \left(4x+3\right)\times 2$$

Use the distributive property to multiply 4x+3 by 2.

$$26-12x\geq 8x+6$$

Subtract 8x from both sides.

$$26-12x-8x\geq 6$$

Combine -12x and -8x to get -20x.

$$26-20x\geq 6$$

Subtract 26 from both sides.

$$-20x\geq 6-26$$

Subtract 26 from 6 to get -20.

$$-20x\geq -20$$

Divide both sides by -20. Since -20 is negative, the inequality direction is changed.

$$x\leq \frac{-20}{-20}$$

Divide -20 by -20 to get 1.

$$x\leq 1$$