Solve 5-sqrt{36}+4(3+1^2)div1/3

$$5 - \sqrt { 36 } + 4 ( 3 + 1 ^ { 2 } ) \div \frac { 1 } { 3 }$$

Evaluate

$$47$$

Solution Steps

Calculate the square root of 36 and get 6.

$$5-6+\frac{4\left(3+1^{2}\right)}{\frac{1}{3}}$$

Subtract 6 from 5 to get -1.

$$-1+\frac{4\left(3+1^{2}\right)}{\frac{1}{3}}$$

Calculate 1 to the power of 2 and get 1.

$$-1+\frac{4\left(3+1\right)}{\frac{1}{3}}$$

Add 3 and 1 to get 4.

$$-1+\frac{4\times 4}{\frac{1}{3}}$$

Multiply 4 and 4 to get 16.

$$-1+\frac{16}{\frac{1}{3}}$$

Divide 16 by \frac{1}{3} by multiplying 16 by the reciprocal of \frac{1}{3}.

$$-1+16\times 3$$

Multiply 16 and 3 to get 48.

$$-1+48$$

Add -1 and 48 to get 47.

$$47$$

Factor

$$47$$