Solve 5-2/b+3/b^2=

$$5 - \frac { 2 } { b } + \frac { 3 } { b ^ { 2 } } =$$

Evaluate

$$5-\frac{2}{b}+\frac{3}{b^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 5 times \frac{b}{b}.

$$\frac{5b}{b}-\frac{2}{b}+\frac{3}{b^{2}}$$

Since \frac{5b}{b} and \frac{2}{b} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5b-2}{b}+\frac{3}{b^{2}}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of b and b^{2} is b^{2}. Multiply \frac{5b-2}{b} times \frac{b}{b}.

$$\frac{\left(5b-2\right)b}{b^{2}}+\frac{3}{b^{2}}$$

Since \frac{\left(5b-2\right)b}{b^{2}} and \frac{3}{b^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\left(5b-2\right)b+3}{b^{2}}$$

Do the multiplications in \left(5b-2\right)b+3.

$$\frac{5b^{2}-2b+3}{b^{2}}$$

Factor

$$\frac{5b^{2}-2b+3}{b^{2}}$$