Solve 5(3-x)<1

$$5 ( 3 - x ) < 1$$

Solve for x

$$x>\frac{14}{5}$$

Solution Steps

Divide both sides by 5. Since 5 is positive, the inequality direction remains the same.

$$3-x<\frac{1}{5}$$

Subtract 3 from both sides.

$$-x<\frac{1}{5}-3$$

Convert 3 to fraction \frac{15}{5}.

$$-x<\frac{1}{5}-\frac{15}{5}$$

Since \frac{1}{5} and \frac{15}{5} have the same denominator, subtract them by subtracting their numerators.

$$-x<\frac{1-15}{5}$$

Subtract 15 from 1 to get -14.

$$-x<-\frac{14}{5}$$

Divide both sides by -1. Since -1 is negative, the inequality direction is changed.

$$x>\frac{-\frac{14}{5}}{-1}$$

Express \frac{-\frac{14}{5}}{-1} as a single fraction.

$$x>\frac{-14}{5\left(-1\right)}$$

Multiply 5 and -1 to get -5.

$$x>\frac{-14}{-5}$$

Fraction \frac{-14}{-5} can be simplified to \frac{14}{5} by removing the negative sign from both the numerator and the denominator.

$$x>\frac{14}{5}$$