Solve 5x^2-8y+3=0

$$5 { x }^{ 2 } -8y+3=0$$

Solve for y

$$y=\frac{5x^{2}+3}{8}$$

Steps for Solving Linear Equation

Subtract 5x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-8y+3=-5x^{2}$$

Subtract 3 from both sides.

$$-8y=-5x^{2}-3$$

Divide both sides by -8.

$$\frac{-8y}{-8}=\frac{-5x^{2}-3}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$y=\frac{-5x^{2}-3}{-8}$$

Divide -5x^{2}-3 by -8.

$$y=\frac{5x^{2}+3}{8}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{40y-15}}{5}$$

$$x=\frac{\sqrt{40y-15}}{5}$$

Solve for x

$$x=\frac{\sqrt{40y-15}}{5}$$

$$x=-\frac{\sqrt{40y-15}}{5}\text{, }y\geq \frac{3}{8}$$